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Start by drawing a chain of five carbon atoms.
Draw a double bond between carbons 2 and 3.
Note that there are two ways to insert the double bond.
One has the ##”H”## atoms on opposite sides of the double bond; the other has the ##”H”## atoms on the same side of the double bond.
cis-Pent-2-ene has the ##”H”##-atoms on the same side of the double bond.
trans-Pent-2-ene has the ##”H”##-atoms on opposite sides of the double bond.
You can also use the Cahn-Ingold-Prelog system to name the isomers.
On each end of the double bond, the alkyl groups (ethyl and methyl) have higher priority than the ##”H”## atoms.
The first isomer has the higher-priority groups on opposite sides. This is (##E##)-pent-2-ene.
The second isomer has the higher-priority groups on the same side. This is (##Z##)-pent-2-ene.
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