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Report (any type)/Brief report
22/09/2021
##ΔH = “-279 kJ”##
This is a Hess’s Law problem.
Our target equation is
2C(graphite) + 2H₂(g) + ½O₂(g) → C₂H₅OH(l); ##ΔH = “?”##
We have the following information:
1. C₂H₅OH(l) + 3O₂(g) → 2CO₂(g) + 3H₂O (l); ##ΔH= “-1367 kJ”##2. H₂(g) + ½O₂(g) → H₂O(l); ##ΔH = “-286 kJ”##3. C(graphite) + O₂(g) → CO₂(g); ##ΔH = “-394 kJ”##
Our target equation has 2C(graphite), so we multiply Equation 3 by 2:
4. 2C(graphite) + 2O₂(g) → 2CO₂(g); ##ΔH = “-798 kJ”##
That means that we also multiply ##ΔH## by 2.
Our target equation has no CO₂, so we reverse equation 1 to cancel the CO₂.
5. 2CO₂(g) +3H₂O(l) → C₂H₅OH(l) + 3O₂(g) ; ##ΔH = “+1367 kJ”##
That means that we also change the sign of ##ΔH##.
Our target equation has no H₂O, so we multiply Equation 2 and its ##ΔH## by 3 to cancel the H₂O:
6. 3H₂(g) + ³/₂O₂(g) → 3H₂O(l); ##ΔH = “-858 kJ”##
Now we add equations 4, 5, and 6 and their ΔH values.
This gives
2C(graphite) + 2H₂(g) + ½O₂(g) → C₂H₅OH(l); ##ΔH = “-279 kJ”##
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I want to thank your team (Jeff) for finding a new writer when you were unable to reach my existing writer to revise my paper. I appreciate your professionalism and efforts. Thanks
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