I want to thank your team (Jeff) for finding a new writer when you were unable to reach my existing writer to revise my paper. I appreciate your professionalism and efforts. Thanks
Report (any type)/Brief report
22/09/2021
THE CONVERSION RATIOS
There is a conversion factor for going from ##”mm Hg”## (or ##”torr”##) to ##”atm”##:
##mathbf(“1 atm” = “760 mm Hg” = “760 torr”)##
There also exists a conversion factor for ##”PSI”##. I actually don’t know it, so I looked it up: https://www.google.com/?gws_rd=sslq=psi+to+torr
Turns out it’s ##mathbf(“51.7149 torr = 1 PSI”)##.
(Google is a great resource. You should practice with it!)
PERFORMING THE CONVERSIONS
(1)
Let’s start from the equality we just wrote out.
##”1 atm”## ##=## ##”760 mm Hg”##
What happens if we divide by ##”1 atm”##? We get the actual ratio for the conversion.
##(1 cancel”atm”)/(1 cancel”atm”)## ##= 1## ##= “760 mm Hg”https://studydaddy.com/”1 atm” = “1 atm”https://studydaddy.com/”760 mm Hg”##
This implies that multiplying by this ratio does NOT change the validity of your answer… only the units. (It preserves your numerical information.)
Thus, we get:
##color(blue)(P_”atm”) = 255 cancel”mm Hg” xx “1 atm”/(760 cancel”mm Hg”)##
##=## ##color(blue)(“0.336 atm”)##
So now you have the same pressure in different units.
(2)
Like before, we have a ratio that is equal to ##1##:
##1 = “51.7149 torr”https://studydaddy.com/”1 PSI” = “1 PSI”https://studydaddy.com/”51.7149 torr”##
This ratio is used as follows:
##color(blue)(P_”torr”) = 620 cancel”torr” xx “1 PSI”/(51.7149 cancel”torr”)##
##=## ##color(blue)(“12.0 torr”)##
Again, the same pressure as ##”620 torr”##, but in different units.
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I want to thank your team (Jeff) for finding a new writer when you were unable to reach my existing writer to revise my paper. I appreciate your professionalism and efforts. Thanks
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