How can I balance this equation? ___ AlBr3 + ____ K2SO4 —> ____ KBr + ____ Al2(SO4)3

##AlBr_3 + K_2SO_4 -> KBr + Al_2(SO_4)_3##

How I balance equations is by first of all dividing the equation into two parts – reactants and products.

Reactants
Al = 3
Br = 3
K = 2
S = 1
O = 4

Products
Al = 2
Br = 1
K = 1
S = 3
O = 12

Remember all atoms within the brackets get multiplied by the number outwith them.

Step 1
Put a 6 before KBr

##AlBr_3 + K_2SO_4 -> 6KBr + Al_2(SO_4)_3##

Step 2
Put a 2 before ##AlBr_3##
– this has now balanced the number of Aluminium and Bromine atoms.

##2AlBr_3 + K_2SO_4 -> 6KBr + Al_2(SO_4)_3##

Step 3
Put a 3 before ##K_2SO_4##

This balances the Potassium, Sulphur and Oxyen

##2AlBr_3 + 3K_2SO_4 -> 6KBr + Al_2(SO_4)_3##

Now check the reactants and products:

Reactants
Al – 2
Br – 6
K – 6
S – 3
O – 12

Products
Al – 2
Br – 6
K – 6
S – 3
O – 12

We have now successfully balanced the equation

I hope this helps!

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