# How can I calculate the partial pressure of a dry gas?

We must use the following equation:

##P_”dry gas” = P_”total” – P_”water vapor”##

Suppose that a sample of hydrogen gas is collected over water at 14.0 °C. The pressure of the resultant mixture is 113.0 kPa. What is the pressure that is exerted by the dry hydrogen alone?

DATA:

##P_”total” = “113.0 kPa” × “760 mmHg”https://studydaddy.com/”101.3 kPa”## = 847.8 mmHg

From Table,

##P_”water vapor”##= 11.99 mmHg

##P_”total”## = ?

SOLUTION:

Now, by inserting the values, we get

##P_”dry gas” = P_”total” – P_”water vapor”##

##P_”dry gas”## = 847.8 mmHg – 11.99 mmHg

##P_”dry gas”## = 835.8 mmHg

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