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Report (any type)/Brief report
22/09/2021
You use the and by mass of the stock solution.
You know that you’re dealing with a ##”1-mol/L”## nitric acid, ##”HNO”””_3##, solution.
To get the solution’s by volume, you would need to have some information about the stock solution of nitric acid used to make the ##”1-mol/L”## solution.
The idea here is that your ##”1-mol/L”## nitric acid solution was prepared by a sample taken from a stock solution of nitric acid. This means that you need to find the volume of the stock solution used to prepare the ##”1-mol/L”## solution in order to be able to find its volume by volume percent concentration.
Usually, nitric acid stock have a percent concentration by mass of nitric acid equal to ##70.2%## and a density of ##”1.41 g/mL”##.
Use nitric acid’s molar mass to determine how many grams of acid you get in your ##”1-mol/L”## solution
##1color(red)(cancel(color(black)(“mole HNO”””_3))) * “63.013 g”/(1color(red)(cancel(color(black)(“mole HNO”””_3)))) = “63.013 g”##
Now focus on finding what volume of the stock solution will contain 63.013 g of nitric acid.
To make calculations easier, assume that you have a ##”1-L”## sample of the stock solution. This sample will have a mass of
##1color(red)(cancel(color(black)(“L”))) * (1000color(red)(cancel(color(black)(“mL”))))/(1color(red)(cancel(color(black)(“L”)))) * “1.41 g”/(1color(red)(cancel(color(black)(“mL”)))) = “1410 g”##
Since nitric acid makes up 70.2% of this mass, you know that the ##”1-L”## stock sample will contain
##1410color(red)(cancel(color(black)(“g solution”))) * (“70.2 g HNO”””_3)/(100color(red)(cancel(color(black)(“g solution”)))) = “989.82 g HNO”””_3##
Now, the volume of this solution that will contain 63.013 g of nitric acid is
##63.013color(red)(cancel(color(black)(“g HNO”””_3))) * “1000 mL stock”/(989.92color(red)(cancel(color(black)(“g HNO”””_3)))) = “63.7 mL”##
So, you prepared your ##”1-mol/L”## nitric acid solution by taking a ##”63.7-mL”## sample of the stock solution and adding enough water to make the total volume of th solution equal to ##”1-L”##.
This means that the volume by volume, ##”%v/v”##, percent concentration of the ##”1-mol/L”## solution is
##”%v/v” = V_(HNO_3)/V_”sol” xx 100##
##”%v/v” = (63.7color(red)(cancel(color(black)(“mL”))))/(1000color(red)(cancel(color(black)(“mL”)))) xx 100 = 6.37 = color(green)(“6.4% v/v”)##
SIDE NOTE The answer will depend on the percent concentration by mass, and implicitly on the density, of the stock solution of nitric acid.
I want to thank your team (Jeff) for finding a new writer when you were unable to reach my existing writer to revise my paper. I appreciate your professionalism and efforts. Thanks
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