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22/09/2021
Question 1: ##K_(sp)= 1.1 xx10^(-11)##
Question 2: ##s= 4.9 xx10^(-12)M##
Quest (1) determine the for magnesium hydroxide ##Mg(OH)_2## where the molar solubility of ##Mg(OH)_2## is ##1.4xx10^(-4) M##?
We will use ICE table to solve this question.
The dissolution of ##Mg(OH)_2## can be written as follows:
##” ” ” ” ” ” ” ” ” ” “## ##Mg(OH)_2(s) -> Mg^(2+)(aq) + 2OH^(-)(aq)##
##” ” ” ” ” ” ## Initial: ## ” ” ” ” ” ” ” ” ” ” ” ” 0 M ” ” ” ” ” ” 0M##
##” ” ” ” ” ## Change: ## – sM ” ” ” ” ” ” ” ” ” +sM ” ” ” ” ” +2s M##
##” ” ” ## Equilibrium: ## ” ” ” ” ” ” ” ” ” ” ” ” s M ” ” ” ” ” ” ” ” ” 2s M##
The expression of ##K_(sp)## can be written as follows:
##K_(sp) = [Mg^(2+)(aq)] *[OH^(-)(aq)]^2##
## => K_(sp) = s*(2s)^2 = 4s^3= 4xx(1.4xx10^-4)^3##
##=> K_(sp)= 1.1 xx10^(-11)##
Quest (2) The ##K_(sp)## for ##Zn(OH)_2## is ##5.0xx10^(-17)## . Determine the molar solubility of ##Zn(OH)_2## in a buffer solution with a ##pH ” of ” 11.5##?
We will use ICE table to solve this question.
##pH = 11.5 => [H^+] = 10^(-11.5)##
##=> [OH^-] =10^(-2.5) = 3.2xx10^(-3) M##
The dissolution of ##Zn(OH)_2## can be written as follows:
##” ” ” ” ” ” ” ” ” ” “## ##Zn(OH)_2(s) -> Zn^(2+)(aq) + 2OH^(-)(aq)##
##” ” ” ” ” ” ## Initial: ## ” ” ” ” ” ” ” ” ” ” ” ” 0 M ” ” ” ” ” 3.2xx10^(-3) M##
##” ” ” ” ” ## Change: ## – sM ” ” ” ” ” ” “” +sM ” ” ” ” ” +2s M##
##” ” ” ## Equilibrium: ## ” ” ” ” ” ” ” ” ” ” ” ” s M ” ” ” ” ” (3.2xx10^(-3) + 2s) M##
The expression of ##K_(sp)## can be written as follows:
##K_(sp) = [Zn^(2+)(aq)] *[OH^(-)(aq)]^2##
##5.0xx10^(-17) =s *(3.2xx10^(-3) + 2s)^2##
Solve for ##s=4.9xx10^(-12)M##
Here is a video that explains the solving of Q2 (start at minute 5:14):
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I want to thank your team (Jeff) for finding a new writer when you were unable to reach my existing writer to revise my paper. I appreciate your professionalism and efforts. Thanks
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