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Report (any type)/Brief report
22/09/2021
The units of constant is derived from equation
PV = nRT.
Where the pressure – P, is in atmospheres (atm) the volume – V, is in liters (L) the moles -n, are in moles (m) and Temperature -T is in Kelvin (K) as in all gas law calculations.
When we do the algebraic reconfiguration we end up with Pressure and Volume being decided by moles and Temperature, giving us a combined unit of atm x L / mol x K. the constant value then becomes 0.0821 atm(L)/mol(K).
If you choose not to have your students work in standard pressure unit factor, you may also use: 8.31 kPA(L)/mol(K) or 62.4 Torr(L)/mol(K).
Temperature must always be in Kelvin (K) to avoid using 0 C and getting no solution when students divide.
There is a variation of the ideal gas law that uses the of the gas with the equation PM = dRT.
Where M is the Molar Mass in g/mol and d is the Density of the gas in g/L.?
Pressure and Temperature must remain in the units atm and K and the Gas Law Constant remains R = 0.0821 (atm) L / (mol) K.
If a 100 g of nitrogen gas compressed in a rigid container at 1.5 atm and 25 C What volume should the container be?
P = 1.5 atm
V = ?
n = 100 g / 28g = 3.57 moles (28 g is the mass of Nitrogen gas ##N_2##
R = 0.0821 atm L / mol K
T = 25 C + 273 = 298K
PV =nRT becomes V = nRT/P
V = 3.57 mol (0.0821 atm L /mol K) (298 K / 1.5 atm
V = 58.2 L
Notice the gas law constant allows to cancel all the units except the liters (L).
I know this was long, but I hope it is helpful
SMARTERTEACHER
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I want to thank your team (Jeff) for finding a new writer when you were unable to reach my existing writer to revise my paper. I appreciate your professionalism and efforts. Thanks
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