I want to thank your team (Jeff) for finding a new writer when you were unable to reach my existing writer to revise my paper. I appreciate your professionalism and efforts. Thanks
Report (any type)/Brief report
22/09/2021
NOTE: ##CH_3OH## is methanol and ##CH_4## is methane.
I will solve for both since both undergo combustion reaction.
So,
1) ##5## ##g## of ##CH_3OH##. The molecular mass of ##CH_3OH## is
##12+3+16+1=32## ##g## ##mol^-1##
So, the moles of ##CH_3OH## are ##5/32=0.15625 ## ##mol##
##10## ##g## of ##O_2## has ##10/32=0.3125## ##mol##
The combustion of methanol produces ##CO_2## and ##H_2O##
So, ##2CH_3OH+3O_2->2CO_2+4H_2O##
Hence, ##2## ##mol## of methanol requires ##3## ##mol## oxygen to undergo complete reaction.
So, ##0.15625## ##mol## of methanol will require ##0.234375## ##mol## oxygen to undergo complete reaction.
Since, amount of oxygen supplied is in excess of what is required entire amt. of methanol will be exhausted.
From the equation,
##2## ##mol## of methanol produces ##2## ##mol## carbon dioxide
##0.15625## ##mol## of methanol will produce ##0.15625## ##mol## of carbon dioxide.
The mass of carbon dioxide##=44xx0.15625=6.875## ##g##
2) ##5## ##g## of ##CH_4##. The molecular mass of ##CH_3OH## is
##12+4=16## ##g## ##mol^-1##
So, the moles of ##CH_4## are ##5/16=0.3125 ## ##mol##
##10## ##g## of ##O_2## has ##10/32=0.3125## ##mol##
The combustion of methane produces ##CO_2## and ##H_2O##
So, ##CH_4+2O_2->CO_2+2H_2O##
Hence, ##1## ##mol## of methane requires ##2## ##mol## oxygen to undergo complete reaction.
So, ##0.3125## ##mol## of methanol will require ##0.625## ##mol## oxygen to undergo complete reaction.
Since, amount of oxygen supplied is less than what is required entire amt. of methanol will not be used up. So, here oxygen is the limiting reactant. The amt. of oxygen available will dictate the amt. of carbon dioxide produced.
From the equation,
##2## ##mol## of oxygen produces ##1## ##mol## carbon dioxide
##0.3125## ##mol## of oxygen will produce ##0.15625## ##mol## of carbon dioxide.
The mass of carbon dioxide##=44xx0.15625=6.875## ##g##
I hope that was helpful. Please take care while naming chemical .
I want to thank your team (Jeff) for finding a new writer when you were unable to reach my existing writer to revise my paper. I appreciate your professionalism and efforts. Thanks
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