I want to thank your team (Jeff) for finding a new writer when you were unable to reach my existing writer to revise my paper. I appreciate your professionalism and efforts. Thanks
Report (any type)/Brief report
22/09/2021
The total vapor pressure is ##”489 torr”##.
This problem requires you to have some idea about Raoult’s Law, which allows you to calculate the partial vapor pressure of a liquid that’s part of a mixture by using the vapor pressure of the pure substance and its mole fraction in the mixture.
##color(blue)(P_”A” = chi_”A” * P_”A”^@)” “##, where
##P_”A”## – the partial vapor pressure of the component;
##chi_”A”## – fraction of the component;
##P_”A”^@## – the vapor pressure of the pure component.
You need to use the molar masses of the two substances to find how many moles of each you have. For carbon disulfide you have
##3.95color(red)(cancel(color(black)(“g”))) * “1 mole”/(76.13color(red)(cancel(color(black)(“g”)))) = “0.0519 moles CS”””_2##
For acetone, you have
##2.43color(red)(cancel(color(black)(“g”))) * “1 mole”/(58.08color(red)(cancel(color(black)(“g”)))) = “0.0418 moles”## ##(“CH”””_3)_2″CO”##
The total number of moles in the mixture is
##n_”total” = n_(CS_2) + n_((CH_3)_2CO)##
##n_”total” = 0.0519 + 0.0418 = “0.0937 moles”##
The mole fraction of carbon sulfide is
##chi_(CS_2) = n_(CS_2)/n_”total”##
##chi_(CS_2) = (0.0519color(red)(cancel(color(black)(“moles”))))/(0.0937color(red)(cancel(color(black)(“moles”)))) = “0.554”##
The mole fraction of acetone is
##chi_”acetone” = n_”acetone”/n_”total”##
##chi_”acetone” = (0.0418color(red)(cancel(color(black)(“moles”))))/(0.0937color(red)(cancel(color(black)(“moles”)))) = “0.446”##
This means that the partial vapor pressure of carbon disulfide is
##P_(CS_2) = chi_(CS_2) * P_(CS_2)^@##
##P_(CS_2) = 0.554 * “616 torr” = color(green)(“341 torr”)##
The partial vapor pressure of acetone will be
##P_”acetone” = 0.446 * “332 torr” = color(green)(“148 torr”)##
The total vapor pressure will be
##P_”total” = P_(CS_2) + P_”acetone”##
##P_”total” = “341 torr” + “148 torr” = color(green)(“489 torr”)##
I want to thank your team (Jeff) for finding a new writer when you were unable to reach my existing writer to revise my paper. I appreciate your professionalism and efforts. Thanks
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