# Calculate the number of oxygen atoms in 120.23 g of iron (II) phosphate, Fe3(PO4)2?

There are eight moles of oxygen atoms in each mole of ##”Fe”_3(“PO”_4)_2″##. To answer this question, you must convert the given mass of ##”Fe”_3(“PO”_4)_2″## to moles of ##”Fe”_3(“PO”_4)_2″##. Then multiply the moles of ##”Fe”_3(“PO”_4)_2″## times eight mol O/1 mol ##”Fe”_3(“PO”_4)_2″## to determine the number of moles of oxygen. Then multiply the moles of oxygen times ##”6.022 x 10″^23## atoms O.

Given/Known:
mass of ##”Fe”_3(“PO”_4)_2″## = ##”120.23g”##
molar mass of ##”Fe”_3(“PO”_4)_2″## = ##”357.478g/mol”##
1 mole ##”Fe”_3(“PO”_4)_2″## contains 8 moles oxygen atoms
1 mole O atoms = ##”6.022 x 10″^23## ##”atoms”##

Unknown:
number of oxygen atoms in ##”120.23g Fe”_3(“PO”_4)_2##

Solution:

1. Convert given mass of ##”Fe”_3(“PO”_4)_2″## to moles.

##”120.23g Fe”_3(“PO”_4)_2″## x ##”1 mol”https://studydaddy.com/”357.478g”## = ##”0.336328mol Fe”_3(“PO”_4)_2″##

2. Convert moles ##”Fe”_3(“PO”_4)_2″## to moles O.

##”0.336328mol”## ##”Fe”_3(“PO”_4)_2″## x ##”8 mol O””/1mol Fe”_3(“PO”_4)_2″”## = ##”2.690624 mol O”##

3. Convert moles O to atoms O.

##”2.690624 mol O”## x ##”6.022 x 10″^23## ##”atoms O””/1 mol O”## = ##”1.6203 x 10″^24″####”atoms O”## (answer rounded to five due to 120.23)

##”120.23g”## ##”Fe”_3(“PO”_4)_2## contains ##”1.6203 x 10″^24″## ##”atoms O”##.

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