I want to thank your team (Jeff) for finding a new writer when you were unable to reach my existing writer to revise my paper. I appreciate your professionalism and efforts. Thanks
Report (any type)/Brief report
22/09/2021
To get the experimental molar ratio, you divide the moles of each reactant that you actually used in the experiment by each other.
EXAMPLE 1
Consider the reaction: ##”2Al” + “3I”_2 → “2AlI”_3##
What is the experimental molar ratio of ##”Al”## to ##”I”_2## if 1.20 g ##”Al”## reacts with 2.40 g ##”I”_2##?
Solution
Step 1: Convert all masses into moles.
##1.20 cancel(“g Al”) × “1 mol Al”/(26.98 cancel(“g Al”)) = “0.044 48 mol Al”##
##2.40 cancel(“g I₂”) × (“1 mol I”_2)/(253.8 cancel(“g I₂”)) = “0.009 456 mol I”_2##
Step 2: Calculate the molar ratios
To calculate the molar ratios, you put the moles of one reactant over the moles of the other reactant.
This gives you a molar ratio of ##”Al”## to ##”I”_2## of ##0.04448/0.009456##
Usually, you divide each number in the fraction by the smaller number of moles. This gives a ratio in which no number is less than 1.
The experimental molar ratio of ##”Al”## to ##”I”_2## is then ##0.04448/0.009456 = 4.70/1## (3 significant figures)
The experimental molar ratio of ##”I”_2## to ##”Al”## is ##1/4.70##
Note: It is not incorrect to divide by the larger number and express the above ratios as 1:0.213 and 0.213:1, respectively. It is just a matter of preference.
EXAMPLE 2
A student reacted 10.2 g of barium chloride with excess silver nitrate, according to the equation
##”BaCl”_2(“aq”) + “2AgNO”_3(“aq”) → “2AgCl(s)” + “Ba(NO”_3)_2(“aq”)##
She isolated 14.5 g of silver chloride. What was her experimental molar ratio of ##”AgCl”## to ##”BaCl”_2##?
Solution
Step 1: Convert all masses into moles
##10.2 cancel(“g BaCl₂”) × (“1 mol BaCl”_2)/(208.2 cancel(“g BaCl₂”)) = “0.048 99 mol BaCl”_2##
##14.5 cancel(“g AgCl”) × “1 mol AgCl”/(143.3 cancel(“g AgCl”)) = “0.1012 mol AgCl”##
Step 2: Calculate the molar ratios
The experimental molar ratio of ##”AgCl”## to ##”BaCl”_2## is ##0.1012/0.04899 = 2.07/1##
Here is a video example:
video from: Noel Pauller
I want to thank your team (Jeff) for finding a new writer when you were unable to reach my existing writer to revise my paper. I appreciate your professionalism and efforts. Thanks
Delivering a high-quality product at a reasonable price is not enough anymore.
That’s why we have developed 5 beneficial guarantees that will make your experience with our service enjoyable, easy, and safe.
You have to be 100% sure of the quality of your product to give a money-back guarantee. This describes us perfectly. Make sure that this guarantee is totally transparent.
Read moreEach paper is composed from scratch, according to your instructions. It is then checked by our plagiarism-detection software. There is no gap where plagiarism could squeeze in.
Read moreThanks to our free revisions, there is no way for you to be unsatisfied. We will work on your paper until you are completely happy with the result.
Read moreYour email is safe, as we store it according to international data protection rules. Your bank details are secure, as we use only reliable payment systems.
Read moreBy sending us your money, you buy the service we provide. Check out our terms and conditions if you prefer business talks to be laid out in official language.
Read more