I want to thank your team (Jeff) for finding a new writer when you were unable to reach my existing writer to revise my paper. I appreciate your professionalism and efforts. Thanks
Report (any type)/Brief report
22/09/2021
You identify the limiting reactant by calculating the moles of product that can be formed from each reactant.
Then you calculate the theoretical yield of product from the amount of the limiting reactant.
EXAMPLE
Aspirin is prepared by the reaction between acetic anhydride and salicylic acid.
##”acetic anhydride + salicylic acid → aspirin + acetic acid”##
##”C”_4″H”_6″O”_3 + “C”_7″H”_7″O”_3 → “C”_9″H”_8″O”_4 + “C”_2″H”_4″O”_2##
##color(white)(mm)”A”color(white)(ml) +color(white)(m) “B”color(white)(mm) →color(white)(mll) “C”color(white)(mll) +color(white)(ml) “D”##
What is the theoretical yield of aspirin (##”C”##) if you reacted 4.32 g of acetic anhydride (##”A”##) with 2.00 g of salicylic acid (##”B”##)?
Solution
The molar masses are
Acetic anhydride = ##”A” = “C”_4″H”_6″O”_3 = “102.1 g/mol”##
Salicylic acid = ##”B” = “C”_7″H”_6″O”_3 = “138.1 g/mol”##
Aspirin = ##”C” = “C”_9″H”_8″O”_4 = “180.2 g/mol”##
Identify the limiting reactant
We calculate the moles of each reactant and then use the molar ratios from the balanced equation to calculate the moles of aspirin.
##”Moles of aspirin from A” = 4.32 cancel(“g A”) × (1 cancel(“mol A”))/(102.1 cancel(“g A”)) × “1 mol C”/(1cancel(“mol A”)) = “0.0423 mol C”##
##”Moles of aspirin from B” = 2.00 cancel(“g B”) × (1 cancel(“mol B”))/(138.1 cancel(“g B”)) × “1 mol C”/(1 cancel(“mol B”)) = “0.0145 mol C”##
##”B”## gives the smaller amount of aspirin, so ##”B”## is the limiting reactant.
Calculate the theoretical yield
##0.0145 cancel(“mol C”) × “180.2 g C”/(1 cancel(“mol C”)) = “2.61 g C”##
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I want to thank your team (Jeff) for finding a new writer when you were unable to reach my existing writer to revise my paper. I appreciate your professionalism and efforts. Thanks
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