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Report (any type)/Brief report
22/09/2021
Chromium(II) oxide.
The first thing to recognize here is that you’re dealing with an , since you hae a transition metal, chromium, ##”Cr”##, bonded to a nonmetal, oxygen, ##”O”##.
The second important thing to recognize here is that chromium, being a transition metal, can have multiple , which is another way of saying that it can form multiple cations.
This means that you’re going to have to use a Roman numeral to describe its oxidation state in the name of the compound.
So, start with what you know. Oxygen, being located in group 16 of , forms ##2-## anions aclled oxide anions, ##”O”^(2-)##.
Now, are always neutral. This means that the positive charge on the chromium cation must balance out the negative charge on the oxide anion.
Since the formula unit for this compound, ##”CrO”##, contains one chromium anion and one oxygen anion, you can say that the charge on the chromium cation must be equal to ##2+##.
When , the cation is always named first, followed by the Roman numeral, when needed, and the anion.
In this case, the Roman numeral that must be used is ##”(II)”##, which means that the name of the compound will be
chromium(II) oxide ##->## ##”CrO”##
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I want to thank your team (Jeff) for finding a new writer when you were unable to reach my existing writer to revise my paper. I appreciate your professionalism and efforts. Thanks
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