# What is the mass of a 1.75L sample of a liquid that has a density of 0.921 g/mL?

The mass is ##”1610 g”##.

##”D”=(“M”)/(“V”)##, where ##”D”## is , ##”M”## is mass, ##”V”## is volume

Known/Given
##”D=0.921 g/mL”##
##”V=1.75 L”xx(1000″mL”)/(1″L”)=”1750 mL”##

Unknown
##”M”##

Equation
##”D”=(“M”)/(“V”)##

Solution
Rearrange the equation to isolate the mass and solve for mass.

##”M”=”D”xx”V”=0.921″g/mL”xx1750″mL”=”1611.75 g=1610 g”## with three .

The following diagram helps to understand how to manipulate the density equation so solve for any of the variables.

The following Density Triangle will help you determine how to solve for any missing variable. Put your finger over the missing variable to see what you need to do to solve for it. For example, if you need to find volume, put your finger over the V, and you get ##”M” -: “D”##.

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