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Report (any type)/Brief report
22/09/2021
73 g
The molecular weight of NaCl is 58.44 g/mol
So, one mole of NaCl weighs 58.44 g.
A 2.5 M solution is 2.5 moles per liter (Molarity is just the number of moles per liter).
Therefore, 0.5 L would contain 1.25 mol. Hence, you would need 1.25 × 58.44 g = 73 g.
As equations:
##M = “moles”https://studydaddy.com/”vol”##
##M = “Molarity”##
##”vol” = “volume (in liters)”##
##”moles” = “grams”/(MW)##
##g = “weight of compound”##
##MW = “molecular weight”##
So,
##M = “moles”https://studydaddy.com/”vol”##
Substitute for moles
##M = (g//MW)/”vol”##
We need ##g##, so rearrange
##M × “vol” = g/(MW)##
##g = M × “vol” × MW##
Put in the numbers:
##g = “2.5 mol/L × 0.5 L × 58.44 g/mol”##
##g = “73 g”##
Personally, I prefer the first approach!
You can find out more about moles and molarity here.
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I want to thank your team (Jeff) for finding a new writer when you were unable to reach my existing writer to revise my paper. I appreciate your professionalism and efforts. Thanks
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