# Write a balanced equation for copper 2 sulfate with sodium carbonate to produce copper 2 carbonate and sodium sulfate. Can you please help me?

Here’s what I got.

First, your general chemical reaction looks like this:

##CuSO_(4(aq)) + Na_2CO_(3(aq)) -> CuCO_(3(s)) darr + Na_2SO_(4(aq))##

Copper(II) sulfate, ##CuSO_4##, and sodium carbonate, ##Na_2CO_3##, are soluble in aqueous solution, which means that they will dissociate into cations and anions.

The reaction produces copper(II) carbonate, ##CuCO_3##, an insoluble solid that precipitates out of solution, and aqueous sodium sulfate, ##Na_2SO_4##.

The complete ionic equation is:

##Cu_((aq))^(2+) + SO_(4(aq))^(2-) + 2Na_((aq))^(+) + CO_(3(aq))^(2-) -> CuCO_(3(s)) darr + 2Na_((aq))^(+) + SO_(4(aq))^(2-)##

The net ionic equation, which you get after eliminating spectator ions, is:

##Cu_((aq))^(2+) + color(red)(cancel(color(black)(SO_(4(aq))^(2-)))) + color(red)(cancel(color(black)(2Na_((aq))^(+)))) + CO_(3(aq))^(2-) -> CuCO_(3(s)) darr + color(red)(cancel(color(black)(2Na_((aq))^(+)))) + color(red)(cancel(color(black)(SO_(4(aq))^(2-))))##

##Cu_((aq))^(2+) + CO_(3(aq))^(2-) -> CuCO_(3(s)) darr##

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