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A good way to figure this out is that “hydro” implies that the anion does not have an oxygen atom, and that you can analogize with the chlorine-based acids that you were probably given.
For example:
##”HCl”##: hydrochloric acid
##”HClO”##: hypochlorous acid
##”HClO”_2##: chlorous acid
##”HClO”_3##: chloric acid
##”HClO”_4##: perchloric acid
None of the acids above that contain oxoanions (such as ##”ClO”_3^(-)##, or ##”ClO”_4^(-)##) have “hydro” in their name.
Furthermore, the halogens all form acids with similar names because they are all in the same group/family. So, they have analogous acid naming schemes:
##”HBr”##: hydrobromic acid
##”HCl”##: hydrochloric acid
##”HI”##: hydroiodic acid
From this, you should be able to figure out that you have:
##”HBr”##: hydrobromic acid
##”HBrO”_3##: bromic acid
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