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When you solve the Ideal Gas Law using a value of 1 mole, the volume calculates to ## **22.4 L** ## per mole.
The at STP is a constant using Avogadro’s value of 22.4 L/mol.
To calculate this we can use the of ##PV=nRT##
At STP (Standard Temperature and Pressure)
P = 1 atm
V = ?
n = 1 mol
R = 0.0821 ##(atmL)/(molK)##
T = 273 K
##(1 atm)(V) = (1 mol) (0.0821 (atmL)/(molK))(273K)##
##V= (1 cancel(mol)) (0.0821 (cancel(atm)L)/(cancel(mol)cancel(K)))(273cancel(K))/(1 cancel(atm))##
##V= 22.4 L##
This is the volume of one mole of gas at STP.
I hope this was helpful.
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